73 in binary = 1001001 (100 1001)
In other bases: hexadecimal 49, octal 111. The binary number has 7 bits.
Divide by 2 repeatedly and note each remainder. Read the remainders from bottom to top.
| Division | Quotient | Remainder |
|---|---|---|
| 73 ÷ 2 | 36 | 1 |
| 36 ÷ 2 | 18 | 0 |
| 18 ÷ 2 | 9 | 0 |
| 9 ÷ 2 | 4 | 1 |
| 4 ÷ 2 | 2 | 0 |
| 2 ÷ 2 | 1 | 0 |
| 1 ÷ 2 | 0 | 1 |
Remainders bottom to top: 1001001.
| Power of 2 | 64 | 32 | 16 | 8 | 4 | 2 | 1 |
|---|---|---|---|---|---|---|---|
| Bit | 1 | 0 | 0 | 1 | 0 | 0 | 1 |
Add the powers of 2 where the bit is 1: 64 + 8 + 1 = 73.
Need another number or the reverse direction? Use the binary to decimal converter or the text to binary converter.
| Decimal | Binary | Hex | Octal |
|---|---|---|---|
| 69 | 1000101 | 45 | 105 |
| 70 | 1000110 | 46 | 106 |
| 71 | 1000111 | 47 | 107 |
| 72 | 1001000 | 48 | 110 |
| 74 | 1001010 | 4A | 112 |
| 75 | 1001011 | 4B | 113 |
| 76 | 1001100 | 4C | 114 |
| 77 | 1001101 | 4D | 115 |